4[5x-4(y-3)]=0

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Solution for 4[5x-4(y-3)]=0 equation:


Simplifying
4[5x + -4(y + -3)] = 0

Reorder the terms:
4[5x + -4(-3 + y)] = 0
4[5x + (-3 * -4 + y * -4)] = 0
4[5x + (12 + -4y)] = 0

Reorder the terms:
4[12 + 5x + -4y] = 0
[12 * 4 + 5x * 4 + -4y * 4] = 0
[48 + 20x + -16y] = 0

Solving
48 + 20x + -16y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-48' to each side of the equation.
48 + 20x + -48 + -16y = 0 + -48

Reorder the terms:
48 + -48 + 20x + -16y = 0 + -48

Combine like terms: 48 + -48 = 0
0 + 20x + -16y = 0 + -48
20x + -16y = 0 + -48

Combine like terms: 0 + -48 = -48
20x + -16y = -48

Add '16y' to each side of the equation.
20x + -16y + 16y = -48 + 16y

Combine like terms: -16y + 16y = 0
20x + 0 = -48 + 16y
20x = -48 + 16y

Divide each side by '20'.
x = -2.4 + 0.8y

Simplifying
x = -2.4 + 0.8y

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